Once you"ve learned about an adverse numbers, friend can likewise learn about negative powers. A an adverse exponent just method that the base is on the wrong side of the fraction line, so you have to flip the basic to the other side. For instance, "x–2" (pronounced as "ecks to the minus two") just method "x2, yet underneath, together in 1/(x2)".

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create x–4 using only positive exponents.

I know that the an unfavorable exponent way that the base, the x, belonging on the other side the the fraction line. But there isn"t a fraction line!


To resolve this, I"ll very first convert the expression into a fraction in the method that any expression have the right to be converted into a fraction: by putting it end "1". The course, when I relocate the base to the other side of the portion line, there will be nothing left top top top. But because anything can likewise be related to as gift multiplied through 1, I"ll leave a 1 top top top.

Here"s what the looks like:


Once i no longer needed the "1" underneath (to create the fraction), ns omitted it, due to the fact that I had the change expression underneath, and also the "times one" doesn"t adjust anything.

compose x2 / x–3 using just positive exponents.

Only among the terms has actually a negative exponent. This method that I"ll just be moving one of these terms. The term through the an adverse power is underneath; this method that I"ll be relocating it up top, to the other side of the fraction line. There currently is a ax on top; I"ll be utilizing exponent rule to integrate these 2 terms.

Once I relocate that denominator up top, i won"t having anything left under (other 보다 the "understood" 1), for this reason I"ll drop the denominator.


The negative power will come to be just "1" when I move the base to the various other side that the fraction line. Anything to the strength 1 is just itself, therefore I"ll be able to drop this power when I"ve moved the base.


Make certain you know why the "2" over does not relocate with the variable: the negative exponent is only on the "x", so only the x moves..

I"ve acquired a number within the strength this time, and a variable, so I"ll should remember to leveling the numerical squaring.

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Unlike the vault exercise, the parentheses expected that the negative power did indeed use to the three and the variable.

create (-5x-1)/(y3) using just positive powers.

The "minus one" power on the x means that I"ll need to move that x to the other side the the portion line. Yet the "minus" on the 5 method only that the 5 is negative. This "minus" is not a power, so the doesn"t to speak anything around moving the 5 anywhere!