Since there can be <-ℓ, ℓ> orientations and since the orbital kind f has ℓ = 3, us should have actually 7 feasible orientations v 2 spins, so $7 imes 2 = 14$, so I believed the exactly answer was D (14).

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However, I got it wrong and the exactly answer is marked as C (2). Is it an error in the test, or to be I absent something?

You"re correct that there space seven possible spatial orientations because that an f-type orbital, and hence seven feasible orbitals in one f-type sub-shell. However, the question specifically asks because that the maximum variety of electrons in one together orbital, and also

*any*single atomic orbital, nevertheless of the sub-shell type specified by $l$, deserve to only hold two electrons. This is by virtue the the Pauli exclusion principle. Fourteen would certainly be the maximum number of electrons across an whole f-type sub-shell, yet the question just asks around one orbital.

The inquiry specifically ask that no.of electron an orbit of f subshell can hold.... Together we recognize that f subshell save on computer 7 orbital and each orbital deserve to hold best 2 electons so exactly answer would certainly be 2..we have the right to simply understand this by acquisition the actual life instance imagine that there is home named f which consists of 7 rooms so likewise in this case house is a subshell and also each room is an orbital... Say thanks to you,

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