This appears to be a bit complicated as usually we say that if slope of a line is #m#, steep of line perpendicular come it is #-1/m#, which way just take the reciprocal and readjust the sign.

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For example if slope of a heat is #3/7#, line perpendicular come it will have actually a slope of #-7/3#. And if steep of a heat is #-2#, steep of heat perpendicular come it will certainly be #1/2#.

What execute we perform if we have actually to discover the slope of a heat perpendicular to a line of steep #0#? The difficulty is #1/0# is not defined.

Way the end is also simpler. As equation the a heat whose slope is #0# is that the type #y=k_1# (here #k_1# a continuous is #y#-intercept - aline parallel to #x#-axis),

equation of line perpendicular come it will be #x=k#, where #k# is another constant. Keep in mind #k# is #x#-intercept the the line #x=k# and this line is upright i.e. Parallel come #y#-axis.


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Meave60
may 9, 2018

The slope of a heat perpendicular come a line through a slope of #0# is undefined. The perpendicular heat is a upright line.


Explanation:

The steep of a heat perpendicular to a line with a slope of #0# is undefined. The perpendicular line is a upright line.

A line with a slope of #0# is a horizontal line. A vertical line would be perpendicular to the horizontal line, yet the slope of a vertical heat is undefined.

For example:

The adhering to points will an outcome in a vertical line due to the fact that the x-coordinates are the same.

#(2,3)# and also #(2,4)#

#m=(4-3)/(2-2)#

#m=1/0#, i m sorry is undefined.

The points stand for a vertical line v an undefined slope.

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EZ together pi
might 9, 2018

You cannot find the slope. You can only say the it will be a upright line and the steep is undefined.


Explanation:

A line with a slope of #0# is a horizontal line.

A line which is perpendicular to a horizontal line is a upright line.

However, the steep of a vertical line is undefined.

So you cannot discover the slope. You have the right to only say the it will be a upright line and the steep is undefined.

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This is since for any readjust in #y# values, there is no change in the #x# values.

Slope = #(Delta y)/(Delta x) = y/0#


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